-
-.SH BUGS
-If
-.I whatnowproc
-is
-.BR whatnow ,
-then
-.B comp
-uses a built\-in
-.BR whatnow ,
-it does not actually run the
-.B whatnow
-program.
-Hence, if you define your own
-.IR whatnowproc ,
-don't call it
-.B whatnow
-since
-.B comp
-won't run it.